Question

Find the HCF of 52 and 117 and express it thyform of 52x+117y

Answer 1

According to Euclid's division lemma  

a=bq+r, 0<=r<b

117=52*2+13

52=13*4+0

13=(117*1)-(52*2)

13=-(52*2)+(117*1)

13=52x+117y

x = (-2), y = 1

Answer 2

According to Euclid's division lemma  

a=bq+r, 0<=r<b

117=52*2+13

52=13*4+0

13=(117*1)-(52*2)

13=-(52*2)+(117*1)

13=52x+117y

x = (-2), y = 1

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