Question

find the HCF of 546,728,1092 using long division method​

Answer 1

Answer:

it's too easy..........

Answer 2

first divide546 ,728,1092by prime number

2|_546 2|_728 2|_1092

3|_273 2|_364 2|_546

7|_91 2|_182 3|_273

13|_13 7|_91 7|_91

|_1 13|_13 13|_13

|_1 |_1

next we have to collect the factors

546=2×3×7×13

728=2³×7×13

1092=2²×3×7×13

then the small exponents will be the hcf

2¹, 3¹, 7¹, 13¹ are have least powers and they are common

when we multiplying them

2×3×7×13=546

therefore 546is the hcf