Question

Find the hcf of 55 and 117 and express it in the form 65 x + 117 y

Answer 1

Answer:

Step-by-step explanation:

117=65x1+52

65=52x1+13

52=13x4+0

HCF (65,117)=13

13=65x+117y

13=65-52x1

13=65-(117-65x1)

13=65x(2)-117x(-1)

The values are x=2 & y=-1.