find the hcf of 56 & 112 by factorization
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Step-by-step explanation:
=> Numbers which have only two factors :- 1 ( one ) and the no. itself are called Prime Numbers.
Prime Factors of 56 = 2×2×2×7.
Prime Factors of 112 = 2×2×2×2×7.
∴ LCM of 56 and 112 = 2×2×2×2×7 = 112.
HCF of 56 and 112 = 2×2×2×7 = 56
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Answer:
factors of 56 : 1, 2, 4, 7, 8, 14, 28, 56.
Prime Factorization of 56: 2×2×2×7 or 23 × 7.
56 = 1,2,4,7,8,14,28,56
Factors of 112: 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112.
Prime Factorization of 112: 2 × 2 × 2 × 2 × 7.
112 = 1, 2, 4, 7, 8, 14, 16, 28, 56, 112.
HCF of 56 & 112 by factorization is 56
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