Math, asked by clintalbert, 1 year ago

Find the hcf of 58 and 112 by prime factorisation

Answers

Answered by gaganpreet7150
0

Answer:

Step-by-step explanation:

The factors of 58 are as

58=2×29

Whereas factors of 112 are as

112=2×2×23

So in both cases 2 is there in each case atleast a single time.

Therefore 2 will be there HCF

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