find the hcf of 60 and 40 by Euclid's division lemma
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Answer:
60= 40×1 +20
40= 20×2 +0
HCF = 20
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HCF(60, 40) = 20
Given:
Numbers 60 and 40
To find:
Find the hcf of 60 and 40 by Euclid's division lemma
Solution:
Euclid's division lemma says that for any two positive integers, a and b where a>b then 'a = bq +r'
Here, q is Quotient and r is Reminder
Mathematically, we can write it as
Dividend = (Divisor × Quotient) + Remainder
Given numbers are 60 and 40, since 60 > 40
Divide 60 by 40,
Apply Euclid's division lemma law to given numbers
⇒ 60 = (40 × 1) + 20
[ when 60 is divided by 20, Quotient = 1 and Reminder = 20 ]
Here, Reminder 20 0
Apply Euclid's division lemma law to 40 and 20
⇒ 40 = (20 × 2) + 0
Here, Reminder is equals to '0'
Therefore, HCF(60, 40) = 20
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