find the HCF of 60 and 405 and Express it in the form of 60q + 405r
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Given : 60 & 405
To find : HCF of 60 and 405
Solution:
HCF of 60 * 405
405 = 60* 6 + 45
60 = 45 * 1 + 15
45 = 15 * 3
15 is the HCF
405 = 60* 6 + 45
putting 45 = 60 - 15
=> 405 = 60* 6 + 60 - 15
=> 405 = 60 * (6 + 1) - 15
=> 15 = 60 * 7 - 405
=> 15 = 60 * 7 + 405 *(-1)
q = 7 & r = - 1
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