Math, asked by mehrab9, 1 year ago

find the HCF of 63, 105 and 147​

Answers

Answered by nathabhijit456
15

Answer:

63 = 3 × 3 × 7

105 = 3 × 5 × 7

147 = 3 × 7 × 7

so HCF WILL BE 7 ×3 =21

HOPE THAT IT'S HELP YOU

Answered by pulakmath007
2

HCF of 63 , 105 and 147 is 21

Given :

The numbers 63 , 105 and 147

To find :

HCF of 63, 105 and 147

Solution :

Step 1 of 3 :

Write down the given numbers

The given numbers are 63 , 105 and 147

Step 2 of 3 :

Prime factorise the given numbers

63 = 3 × 3 × 7

105 = 3 × 5 × 7

147 = 3 × 7 × 7

Step 3 of 3 :

Find HCF of 63, 105 and 147

We know that for the given two or more numbers HCF is the greatest number that divides each of the numbers

Hence the required HCF

= HCF of 63, 105 and 147

= 3 × 7

= 21

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