find the HCF of 63, 49, 35
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3
Answer:
Step-by-step explanation:
Option:
A. (72, 40,24)B. (72, 48, 24)C. (64, 40, 28)D. (81, 63, 45)
Answer: D . (81, 63, 45)
Justification: Each set consists of numbers which are obtained by multiplying a certain number by 9, 7 and 5 respectively.
Thus, in the given set, 63 = 7 * 9, 49 = 7 * 7, 35 = 7 * 5.
Similarly, 81 = 9 * 9, 63 = 9 * 7, 45 = 9 * 5.
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Answered by
6
H.C.F of 63,49,35
By prime factorisation method.
63=3*3*7
49=7*7
35=5*7
so H.C.F of given pair is 7
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