Math, asked by menagakamali, 4 months ago

find the hcf of 64, 80 by using prime factorisation?​

Answers

Answered by somethingscoolhere
1

Answer:

The answer will be 16.

Step-by-step explanation:

Prime factorization will be-

64- 2x2x2x2x2x2

80-2x5x2x2x2

So

it would be 2x2x2x2

= 16.

Answered by aftabahemad
1

Answer:

HCF of the given number will be 16

Step-by-step explanation:

In context to question asked,

We have to determine the HCF

As per question,

We have,

64, 80

As it is mentioned to determine the HCF by using prime factorisation method.

We know that,

  • HCF of two or more number is that particular number which is the highest common factors of all the given number.
  • Prime factorisation method is the method in which we convert the given number as a factors of prime numbers.
  • Prime numbers are those numbers which are either divisible by 1 or itself.
  • HCF of any prime number is always 1

So, converting the given number in form of prime numbers,

We will get,

64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2\\80 = 2 \times 2 \times 2 \times 2 \times 5\\=>HCF=2\times 2 \times 2 \times 2= 16(Common\:Numbers)

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