find the HCF of 65 and 117 and express it in the form 65m +117n
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Answer: m=2 n=(-1)
Step-by-step explanation:
( step 1- find the HCF using Euclid's division lemma)
117=65*1+52------------(1)
65=52*1+13---------(2)
52=13*4+0
thus, HCF(117,65)=13
according to the problem,
HCF = 65m+117n
13=65m+117n
( from (2))-
13=65-52
13=65-(117-65) ( since 52=117-65 from (1)
13=65-117+65
13=2(65)-117
thus, m=2 and n=(-1)
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