Find the HCF of 65 and 117 and express it in the form of 65m + 117n.
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HCF of 65 and 117 is 13
- HCF of given numbers is the highest common factor of given numbers.
- Finding HCF using Euclid's Division algorithm:
- Statement: If there are two positive integers a and b then there exists two unique integers q and r such that
a = bq + r (0 ≤ r < b)
- Given numbers are 65, 117
117 = 65 x 1 + 52 ----------------(1)
65 = 52 x 1 + 13 ----------------(2)
52 = 13 x 4 + 0
- Therefore, HCF of 65 and 117 is 13.
- Now, expressing 13 in the form of 65m + 117n
13 = 65 - 52 [from (2)]
13 = 65 - (117 - 65) [from (1)]
13 = 65 - 117 + 65
13 = 65 x 2 - 117 x 1
13 = 65 x 2 + 117 x (-1)
13 = 65m + 117n
Where m = 2, n = -1
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