find the HCF of 65 and 117 express in the form of 65m + 117n
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m=2 n= -1. is your answer
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Answer:
Step-by-step explanation:
By euclid's division algorithm, we get HCF as 13
117 = 65 x 1 + 52
65 = 52 x 1 + 13
52 = 13 x 4 + 0
HCF = 13 = 65 - 52 X 1
= 65 - ( 117 - 65 X 1 ) X 1
= 65 X 2 - 117 X 1
= 65 m + 117 n ( where m = 2 n = -1 )
ritika8634:
how you got 65 ×2- 117×1
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