Math, asked by sameernazia3, 3 months ago

FIND THE HCF of 6abc, 24ab²,12a²b

pls fast ​

Answers

Answered by navinnagda07
1

Answer:

6abc=3×2×a×b×c

24ab^2=3×4×2×a×b×b

12a^2b=3×2×2×a×a×b

hcf=32ab

Answered by prithapaul35
1

Answer:

24ab² = 24×a×b²×c⁰

12a²b = 12×a²×b²×c⁰

6abc = 6×a×b×c

HCF of 6,24 and 12 = 6

HCF of a,a and a² = a

HCF of b,b² and b = b

HCF of c,c⁰ and c⁰ = 1

note:- c⁰=1

so total HCF of 6abc, 24ab² and 12a²b

reson why HCF of a and a²=a

because a²=a×a

and a is the only factor in a² and a

so the HCF of 6abc 24ab²12a²b

is 6×a×b×1 = 6ab

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