find the HCF of 805,1127 and 1449
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805 = 161×5×1
1127 = 161×7×1
1449 = 161×3×3×1
Therefore,
HCF of 805,1127 and 1449 is = 161×1 = 161
1127 = 161×7×1
1449 = 161×3×3×1
Therefore,
HCF of 805,1127 and 1449 is = 161×1 = 161
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