Find the hcf of 81 and 237 and express it as a linear combination of 81 and 237
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237=81*3+3
81=27*3+0
There fore 3 is the hcf
3=81-27*3
=81-27*237-81*3
=81*-2-27*237
81=27*3+0
There fore 3 is the hcf
3=81-27*3
=81-27*237-81*3
=81*-2-27*237
Anonymous:
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