Math, asked by piyush92286, 5 months ago

Find the HCF of 86 and 404 by prime factorization method. Hence find their LCM.

Answers

Answered by kalpeshdpatil1
0

Find the HCF of 86 and 404 by prime factorization method. Hence find their LCM

By Prime factorisation method, prime factors of 96 and 404 are:

96=2×2×2×2×2×3

404=2×2×101

HCF = Product of common primes factors in given numbers.

∴ HCF of 96 & 404 = 2×2=4

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Answered by BlackWizard
3

HCF of 86 and 404 = 2

LCM of 86 and 404 = 17372

Step-by-step explanation:

GIVEN NUMBERS

86

404

___________________________

TO FIND

HCF

___________________________

HCF OF 86

86 / 2 = 43

43 / 43 = 1

86 = 1 × 43

86 = 1¹ × 43¹

  \underline 2 |86 \\ 1 |43 \\  | 1 \\ 86=  {2}  \times {43} \\ 86 ={2}^{1}  \times  {43}^{1}

___________________________

HCF OF 404

404 / 2 = 202

202 / 2 = 101

101 / 101 = 1

HCF = 2 × 2 × 101

HCF = 2²× 101¹

2|404\\ 2|202 \\101|101 \\  |1 \\ 404 = 2 \times 2 \times 101 \\ 404 =  {2}^{2}  \times 101

HCF = 2

HCF of 86 and 404 = 2

___________________________

Now Let's find the LCM of 86 and 404

W know that,

HCF + LCM = Products of Number

2 + LCM = 86 × 404

LCM = 86 × 404 / 2

 LCM =  \frac{86 \times 404}{2}

LCM = 34744 / 2

LCM =   \frac{34744}{2}

LCM = 17372

LCM = 17372

LCM of 86 and 404 = 17372

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