Question

find the HCF of 9/12 , 12/25 , 18/35 , 21/40​

Answer 1

Answer:

HCF of 9/10 ,12/25 ,18 ,35 ,21/40=HCF of nominator /LCM of denominatorHCF (9,12,18,35,21)9=3 x 312= 2 x 2 x 318=2 x 3 x 335=7 x 521=7 x 3common factor=1hence HCF (9,12,18,35,21)=1nowLCM (10,25,1,1,40)=200hence of given number is

HCF of 9/10 ,12/25 ,18 ,35 ,21/40=HCF of nominator /LCM of denominatorHCF (9,12,18,35,21)9=3 x 312= 2 x 2 x 318=2 x 3 x 335=7 x 521=7 x 3common factor=1hence HCF (9,12,18,35,21)=1nowLCM (10,25,1,1,40)=200hence of given number is=1/200

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