Math, asked by kamalhans894, 5 months ago

Find the HCF of 902, 1394 and 3321.​

Answers

Answered by kartik6284688250
4

902 = 2*11*41*1 ( product of Prime factor of 902)

1394=2*41*17*1 ( product of Prime factor of 1394)

3321=3*3*3*3*41*1 ( product of Prime factor of 3321)

take all Commen prime factor of all these

numbers

that is 41 and 1

multiply the common prime Factor

41*1=41

HCF of 902 ,1394,3321 is 41

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