Find the hcf of 918 and 162 y euclid's division lemma
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a=918 and b=162
a=bq+r
918=162*5+108
162=108*1+54
108=54*2+0
thus 54 is the HCF of 918 and 162
a=bq+r
918=162*5+108
162=108*1+54
108=54*2+0
thus 54 is the HCF of 918 and 162
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