Question

find the HCF of 96 and 404 by prime factorisation​

Answer 1

The answer is above step by step solved

Answer 2

Answer:

Here, a=96=16∗6=25∗31

b=404=4∗101=22∗1011

So, HCF will be the common factor with their least power.

In this case, common factor is 2 and its least power is 2.

So, HCF=22=4

As, we know,

a∗b=HCF∗LCM

LCM=a∗bHCF=96∗4044=9696

hope it helpful