Math, asked by itzmanu48, 9 months ago

Find the HCF of 96 and 404 by prime factorisation and use it to find the LCM

Answers

Answered by ThakurRajSingh24
19

Solution :-

Let a=404 and b=96

Expressing the number as a product of prime number

404=2×2×101

96=2×2×2×2×2×3

∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

∴ HCF of 404 and 96 is 2×2=4

Now HCF×LCM=4×9696=38784

Product of two given numbers 404×96=38784

Hence HCM×LCM= product of two given numbers.

Answered by manjaykumardrcc95
2

Step-by-step explanation:

404 = 2 x 2 x 101

96 = 2 x 2 x 2 x 2 x 2 x 3

So, HCF = 2 x 2 = 4

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 101 = 9696

HCF x LCM = 4 x 9696 = 38764

Product of given numbers = 404 x 96 = 38764

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