Question

Find the HCF of 96 and 404 by prime factorisation method amd hence find their LCM.​

Answer 1

Step-by-step explanation:

Components: Electrons and a compact nucleus of protons and neutrons

Electric charge: zero (neutral), or ion charge

Mass range: 1.67×10−27 to 4.52×10−25 kg

Diameter range: 62 pm (He) to 520 pm (Cs) (data page)

Answer 2

$\huge\star{\underline{\mathtt{\red{A}\pink{n}\green{s}\blue{w}\purple{e}\orange{r}}}}$

$\longrightarrow$$\sf\pink{96=2×2×2×2×2×3={2}^{5}\times{3}^{1}}$

$\longrightarrow$$\sf\red{404=2×2×101={2}^{2}\times{101}^{1}}$

$\Large\sf\underline\green{Therefore,}$

$\longrightarrow$$\sf\purple{HCF\:=\:2\:×2\:=\:4}$

$\Large\sf\underline\orange{Also,}$

$\longrightarrow$$\sf\blue{HCF\:×\:LCM\:=\:product\:of\:2\:numbers}$

$\longrightarrow$$\sf\orange{4\:×\:LCM\:=\:96\:×\:404}$

$\longrightarrow$$\sf\pink{LCM= \frac{96 \times 404}{4}}$

$\longrightarrow$$\sf\red{LCM\:=\:96\:×\:101}$

$\longrightarrow$$\large\sf\green{LCM\:=\:9696}$

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

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