Question

Find the HCF of 96 and 404 by prime factorisation method amd hence find their LCM.​

Answer 1

${ \underline { \underline{ \sf \blue{Required \: answer - }}}}$

$\longrightarrow \sf\pink{96=2×2×2×2×2×3={2}^{5}\times{3}^{1}}[tex] </p><p></p><p>\longrightarrow\sf\red{404=2×2×101={2}^{2}\times{101}^{1}} </p><p></p><p>\LARGE\underline\sf\green{Therefore,} </p><p></p><p></p><p>[tex]\longrightarrow \sf\purple{HCF\:=\:2\:×2\:=\:4}$

$\Large\sf\underline\orange{Also,}$

$\longrightarrow \sf\blue{HCF\:×\:LCM\:=\:product\:of\:2\:numbers}$

$\longrightarrow\sf\pink{LCM= \frac{96 \times 404}{4}}$

$\longrightarrow \sf\red{LCM\:=\:96\:×\:101}\\</p><p>\longrightarrow\large\sf\green</p><p>{LCM\:=\:9696}</p><p>$

Answer 2

Answer:

HCF of 96 and 404 by prime factorisation method:-

Since, 96 = 2 × 2 × 2 × 2 × 2 × 3

and, 404 = 2 × 2 × 101

So, HCF of 96 and 404 = Product of common prime factors

                                 = 2 × 2 = 4

LCM = 2 × 2 × 2 × 2 × 2 × 101 × 3

       = 9696

Explanation:

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