Question

Find the HCF of 960 and 432​

Answer 1

Answer :

Let a and b are two positive

integers . Then there exists two

unique whole numbers q and r

such that  

a=bq+r,

0≤r<0

Now ,

Start with the larger integer , that  

is 960 , Apply the division lemma

to 960 and 432, to get

960=432×2+96

432=96×4+48

96=48×2+0

The remainder has now become  

zero , so our procedure stops.

Since , the divisor at this stage is  

48,

Therefore ,

HCF(960,432)=48

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Answer 2

Answer:

48 is the HCF(Highest Common Factor)