Math, asked by kamal3514, 1 year ago

find the HCF of-(a)-18,48(b)-34,102 (c)-98,112 ?

Answers

Answered by gamer1234

0

Answer:

(a)18=2*3*3

48=2*2*2*2*3

HCF=2*3=6

(b)34=2*17

102=2*3*17

HCF =2*17=34

(c)98=2*7*7

112=2*2*2*2*7

HCF =2*7=14

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