Question

find the hcf of (a^2-a)(a+1)​

Answer 1

$\underline{\textsf{Given:}}$

$\mathsf{a^2-a}\;\textsf{and}\;\mathsf{a+1}$

$\underline{\textsf{To find:}}$

$\textsf{H.C.F of the given polynomials}$

$\underline{\textsf{Solution:}}$

$\textsf{First we factorize the given polynomials into linear factors}$

$\mathsf{a^2-a=a(a-1)=1{\times}a{\times}(a-1)}$

$\mathsf{a+1=1{\times}(a+1)}$

$\textsf{There is no factors in common except 1}$

$\therefore\textsf{H.C.F=1}$

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