Question

Find the HCF of:
(a) 32 and 56. (b) 90 and 105​

Answer 1

Using Prime Factorisation Method

(a) 32 and 56

32=2×2×2×2×2

56=2×2×2×7

HCF of 32 and 56=2×2×2=8

(b) 90 and 105

90=2×3×3×5

105=3×5×7

HCF of 90 and 105=3×5=15