Question

Find the HCF of a3 - a2x, a3 - ax, a4-ax?​

Answer 1

Concept Introduction:-

The largest common divisor of more than or two in mathematics numbers that are not all equal to zero is biggest positive number that divides each integer by itself.

Given Information:-

We have been given that $a^3 - a^2x, a^3 - ax, a^4-ax$

To Find:-

We have to find that the HCF of $a^3 - a^2x, a^3 - ax, a^4-ax$

Solution:-

According to the problem

$a^3 - a^2x=a^2(a-x)\\a^3 - ax=a(a^2-x)\\a^4-ax=a(a^3-x)$

The Common factor of all is $a$

Final Answer:-

The HCF of $a^3 - a^2x, a^3 - ax, a^4-ax$ is $a$.

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