find the HCF of a³-ab² and a⁴+2a³b+a²b²
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0
Answer:
I think for this question answer should have long derived
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2
Answer:
a(a+b)
Step-by-step explanation:
taking 'a' as common factor in the first place
=a²-b²
=a(a+b)(a-b)
in the second place the second polynomials results to the expression of (a+b)³ when taking variables 'a'as common factor
hence ,a(a+b)
is the reason right answer
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