Question

find the HCF of each set of number using prime factorisation method
(i) 51,85
(ii) 61,76
(iii) 84,120
(iv) 27,45,81
(v) 45,55,95
please answer this question fast i want to write​

Answer 1

Answer:

(i)17

(ii)1

(iii)12

(iv)9

(v)5

Step-by-step explanation:

(i)

51=3×17

85=5×17

HCF =17

(ii)

61=1×61

76=2×2×19

HCF=1

(iii)

84=2×2×3×7

120=2×2×2×3×5

HCF=2×2×3=12

(iv)27=3×3×3

45=3×3×5

81=3×3×3×3

HCF=3×3=9

(v)45=3×3×5

55=5×11

95=5×19

HCF=5

I hope you understand.