Find the HCF of each set of numbers using prime factorization method: 3. 66, 77
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Step-by-step explanation:
by prime factorisation we get
3= 3*1
66=2*3*11*1
77=7*11*1
Hcf= product of cooman terms with lowest power
hcf = 1 ans
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Answer:
by prime factorisation we get
3= 3*1
66=2*3*11*1
77=7*11*1
Hcf= product of cooman terms with lowest power
hcf = 1 ans
Step-by-step explanation:
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