Math, asked by gopigopika977, 1 month ago

Find the HCF of each set of numbers using prime factorization method: 3. 66, 77​

Answers

Answered by vivekvish8765
0

Step-by-step explanation:

by prime factorisation we get

3= 3*1

66=2*3*11*1

77=7*11*1

Hcf= product of cooman terms with lowest power

hcf = 1 ans

Attachments:
Answered by apsarvan
1

Answer:

by prime factorisation we get

3= 3*1

66=2*3*11*1

77=7*11*1

Hcf= product of cooman terms with lowest power

hcf = 1 ans

Step-by-step explanation:

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