Question

Find the HCF of each set of numbers using prime factorisation method. 8 , 12

Answer 1

Answer:

after solving the question you get HCF =4

Answer 2

8, 12 8 = 2 × 4 = 2 × 2 × 2 12 = 2 × 6 = 2 × 2 × 3 Product of common factors = 2 × 2 = 4 Product of other factors = 2 × 3 = 6 LCM = Product of common factors × Product of other factors = 4 × 6 = 24 LCM (8, 12) = 24. (iii) 10, 15 10 = 2 × 5 15 = 3 × 5 Product of common factors = 5 Product of other factors = 2 × 3 = 6 LCM (10, 15) = Product of common factors × Product of other factors = 5 × 6 = 30Read more on Sarthaks.com - https://www.sarthaks.com/1020063/find-the-lcm-of-each-set-of-numbers-using-prime-factorisation-method-i-6-9-ii-8-12-iii-10-15

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