Question

find the hcf of f(x)= 2x²-18 and g(x)= x³+27​

Answer 1

Let f(x) = x³ + 27

Let f(x) = x³ + 270 = x³ + 27

Let f(x) = x³ + 270 = x³ + 27x³= -27

Let f(x) = x³ + 270 = x³ + 27x³= -27x = -3

Let f(x) = x³ + 270 = x³ + 27x³= -27x = -3This means that x = -3 is the only zero of the graph of f(x). Since we know

Let f(x) = x³ + 270 = x³ + 27x³= -27x = -3This means that x = -3 is the only zero of the graph of f(x). Since we know (x+3)

Let f(x) = x³ + 270 = x³ + 27x³= -27x = -3This means that x = -3 is the only zero of the graph of f(x). Since we know (x+3) is one factor of

Let f(x) = x³ + 270 = x³ + 27x³= -27x = -3This means that x = -3 is the only zero of the graph of f(x). Since we know (x+3) is one factor of f (x) , to find the 2nd factor,

, to find the 2nd factor, x

, to find the 2nd factor, x3

, to find the 2nd factor, x3+

, to find the 2nd factor, x3+27

, to find the 2nd factor, x3+27x

, to find the 2nd factor, x3+27x+

, to find the 2nd factor, x3+27x+3

, to find the 2nd factor, x3+27x+3We get the second factor to be

, to find the 2nd factor, x3+27x+3We get the second factor to be x^2−3x+9

2−3x+9.

2−3x+9.Therefore,

2−3x+9.Therefore, f(x)

= (x+3) (x^2−x^3+9)

I hope it will helpful for u