Question

find the HCF of f(x) = (2x² – 4x), g(x) = (3x4 – 12x2) and h(x) = (2x5 – 2x4 – 4x3)​

Answer 1

Step-by-step explanation:

1. Factor of (2x2-4x)

=(2x2-4x)

=2x(x-2)

= 2 x( x - 2)

2. Factor of (3x4-12x2)

=(3x4-12x2)

=3x2(x2-4)

Rewrite x2=(x)2 and 4=(2)2

=3x2((x)2-(2)2)

Here both terms are perfect squares, so factor using the difference of squares formula, a2-b2=(a-b)(a+b) where a=x and b=2

=3x2(x-2)(x+2)

= 3 x2( x - 2)( x + 2)

3. Factor of (2x5-2x4-4x3)

=(2x5-2x4-4x3)