find the HCF of f(x) =(x²-y²) g(x) =12(x+1) (x-3) (x-1)
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Step-by-step explanation:
Given, HCF of p(x) and q(x) is 2x(x+2) and LCM =24x(x+2)
2
(x−2), p(x)=8x
3
+32x
2
+32
q(x)=
p(x)
HCF×LCM
;p(x)=8x(x+2)
2
=
8x(x+2)
2
2x(x+2)×24x(x+2)
2
(x−2)
=6x(x+2)(x−2)
=6x(x
2
−4)
=6x
3
−24x
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