Question

find the HCF of following number by the prime factorization method
(a) 14;56and98
(b) 112;140and168​

Answer 1

First we will find the prime factors of a)14,56 and 98

14 = 2×7

56 = 2×2×2×7

98 = 2×7×7

H.C.F =2×7=14

b) 112,140 and 168

112 = 2×2×2×2×7

140 = 2×2×5×7

168 = 2×2×2×3×7

H.C.F = 2×2×7=28

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Answer 2

Answer:(a)14

(B)28

Step-by-step explanation:(a) first we will find the prime factors of 14 ,56 and 98

14=2×7

56=2×2×2×7

98=2×7×7

Now we will common out the common factors

So HCF=2×7=14

(B)first we will find the prime factors of 112,140 and 168

112=2×2×2×2×7

140=2×2×5×7

168=2×2×2×3×7

Now we will common out the common factors

So HCF=2×2×7=28

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