Find the HCF of following polonomials 18 (x³-x³+x-1),12(x⁴-1)
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Answer:
Sin^2 x + sin x - 1 = 0
sin x = [ √5 - 1] /2 = cos² x
cos⁴ x = (5+1-2√5)/4 = (3 -√5)/2
cos⁸ x = (9+5- 6√5)/4 = (7- 3√5)/2
3 cos¹° x + cos¹² x
= cos⁸ x * (3 cos² x + cos⁴ x)
= (7 - 3√5)/2 * [ 3 (√5 -1)/2 + (3 - √5)/2 ]
= (7 - 3√5)/2 * √5
= (7 √5 - 15)/2
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