Find the hcf of k 2k 3k 4k 5k with cage any positive integer
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Answered by
1
HCF of k 2k 3k 4k & 5k.
k = k*1
2k = 2*k
3k = 3*k
4k = 2*2*k
5k = 5*k
So the HCF= k
k = k*1
2k = 2*k
3k = 3*k
4k = 2*2*k
5k = 5*k
So the HCF= k
Answered by
0
HCF :- the highest common factor
since in above given number that is k , 2k , 3k , 4k and 5k the only common factor is k
So,
k is the HCF
since in above given number that is k , 2k , 3k , 4k and 5k the only common factor is k
So,
k is the HCF
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