find the HCF of (lm cube, l square m where l and m are prime
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Answer:
l¹m¹
Step-by-step explanation:
HCF of ( lm³,l²m) is equal to= lm
this can be obtained be taking the least exponents of each factor in all the number.
least power of l in lm³ and l²m is l¹
least power of m in lm³ and l²m is m¹
therefore HCF is l¹m¹
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