Question

find the hcf of monomial 9x3y and 18x2y3 pls tell urgent
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Answer 1

Answer:

the monomial of 9x ,3y is 3

the monomial of. 18x, 2y^3 is 2

Answer 2

$Given \: monomials \:9x^{3}y \:and \: 18x^{2}y^{3}$

/* We have */

9x³y = 3×3×x ×x×x ×y

18x²y³ = 2 ×3×3 ×x× x × y × y × y

$\red{HCF \: of \: 9x^{3}y \:and \: 18x^{2}y^{3} }$

$\green { = 3\times 3 \times x\times x \times y } \\= \green { = 9x^{2}y }$

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