Question

find the HCF of of 12 and 45 and 75​

Answer 1

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$hcf \: of \: 12 \: and \: 45 \: and \: 75 \: is$

The HCF of three numbers i.e HCF(12, 45, 75)=3

Given 3 numbers 12, 45 and 75

we have to find the HCF of above 3 numbers

we will find the HCF by prime factorization method

The factors are

12=2\times 2\times 312=2×2×3

45=3\times 3\times 545=3×3×5

75=3\times 5\times 575=3×5×5

The highest common factor from the above these factors is 3

Hence, HCF(12, 45, 75)=3

Answer 2

Step-by-step explanation:

HCF 12=2×2×3

45=5×3×3

75=5×3×5

common factor=3

HCF of 12,45,75=3