find the HCF of pairs of integers Express it as a linear combination of 506 and1155
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Answer:
1155 = 506 × 2 + 143
506 = 143 × 3 + 77
143 = 77 × 1 + 66
77 = 66 × 1 + 11
66 = 11 × 6 + 0
H.C.F = 11
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