Question

find the HCF of polynomial 2xsquar-8,4x+8 and 8(x square +4x+4) ​

Answer 1

Answer:

2x²-8=2(x²-4)

=2(x²-2²)

=2(x+2)(x-2)

4x+8=4(x+2)

8(x²+4x+4)=8(x²+2x+2x+4)

=2³[x(x+2)+2(x+2)]

=2³(x+2)(x+2)

=2³(x+2)²

HCF=2(x+2)