Math, asked by rampalsharma54, 9 months ago

find the HCF of roots of linear equation system x+2y=12,2x-3y=3​

Answers

Answered by RitaNarine
0

Given:

Linear equation system x+2y=12, 2x-3y=3​

To Find:

HCF of roots of linear equation system.

Solution:

Solving x+2y=12, 2x-3y=3​

  • x + 2y = 12 - ( 1 )
  • 2x - 3y = 3 - ( 2 )

Solving for y,

  • 2 x ( 1 ) - ( 3 ) = > (2x + 4y = 24 ) - ( 2x - 3y = 3 )
  • 7y = 21
  • y = 3.

Solving for x ,

  • x = 12 - 6 = 6 .

Now we have to find the Highest Common Factor of 6 and 3 .

  • Factors of 3 : 1, 3.
  • Factors of 6: 1 , 2, 3, 6.

Therefore, HCF( 3, 6 ) = 3

The HCF of roots of linear equation system x+2y = 12, 2x-3y=3​ is 3.

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