Question

Find the HCF of the following
by division methood
(a) 60, 96 and 150​

Answer 1

Answer:

hope this helps you ...........

Answer 2

Answer:

the prime factor of 60 = 2×2×3×5

the prime factor of 96 = 2×2×2×2×2×2×3

the prime factor of 150= 2×3×5×5

so the HCF = 3×2 = 6