Question

Find the HCF of the following by prime factorisation.

56,252..
​

Answer 1

Express 18 and 45 as product of primes.

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2 45=3×3×5=3 2 ×5

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2 45=3×3×5=3 2 ×5∴ HCF of 18 and 45=3×3=9

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2 45=3×3×5=3 2 ×5∴ HCF of 18 and 45=3×3=9LCM of 18 and 45=3×3×2×5=90

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2 45=3×3×5=3 2 ×5∴ HCF of 18 and 45=3×3=9LCM of 18 and 45=3×3×2×5=90Recall : HCF of any 2 positive integers is the product of the smallest power of each common prime factor of the numbers.

Express 18 and 45 as product of primes. 18=2×3×3×=2×3 2 45=3×3×5=3 2 ×5∴ HCF of 18 and 45=3×3=9LCM of 18 and 45=3×3×2×5=90Recall : HCF of any 2 positive integers is the product of the smallest power of each common prime factor of the numbers. LCM of any 2 positive integers is the product of the greatest power of each factor of the numbers.

Answer 2

Step-by-step explanation:

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