Math, asked by divyadivya1743, 3 months ago

find the HCF of the following By prime _factorisation and by continued division method

(a) 48,64 (b) 123,216 (c)40,60,56 (d) 10,35,40​

Answers

Answered by Anonymous
0

Step-by-step explanation:

(a) The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 64 are: 1, 2, 4, 8, 16, 32, 64

Then the Highest common factor is 16.

(b)The factors of 123 are: 1, 3, 41, 123

The factors of 216 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 108, 216

Then the Highest common factor is 3.

(c)The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Then the Highest common factor is 4.

(d) The factors of 10 are: 1, 2, 5, 10

The factors of 35 are: 1, 5, 7, 35

The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40

Then the Highest common factor is 5.

Answered by bvprasadkumar
1

Answer:

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The tex2jax preprocessor can be configured to look for whatever markers you want to use for your math delimiters. See the tex2jax configuration options section for details on how to customize the action of tex2jax

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