find the hcf of the following by prime factorisation method 522,1276 and 1624
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H.C.F of 5221276 and 1624 is
by Euclid's algorithm
5221276=1624×3200+24476
1624=24476×0+1624
24476=1624×15+110
1624=110×14+84
110=84×1+26
84=26×3+6
26=6×4+2
6=2×3+0
therefore,2 is the HCFof 5221276 and 1624
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