find the hcf of the following by PRIME factorisation METHOD:problem 140,96?
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HCF of 140 and 96 is 4
factors of 140 = 2×2×5×7
and 96= 2×2×2×2×2×3
2×2 is common in both so HCF of 140 and 96 is 4
factors of 140 = 2×2×5×7
and 96= 2×2×2×2×2×3
2×2 is common in both so HCF of 140 and 96 is 4
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